BAEL-4523 - Added code example for article to find the largest power of 2 that is less than the given number (#9840)

This commit is contained in:
KarthikBalaraman
2020-08-27 23:02:43 +05:30
committed by GitHub
parent 3e2441bd51
commit 230fd8d849
2 changed files with 127 additions and 0 deletions

View File

@@ -0,0 +1,60 @@
package com.baeldung.algorithms.largestpowerof2;
import org.nd4j.linalg.io.Assert;
public class LargestPowerOf2 {
public long findLargestPowerOf2LessThanTheGivenNumber(long input) {
Assert.isTrue(input > 1, "Invalid input");
long firstPowerOf2 = 1;
long nextPowerOf2 = 2;
while (nextPowerOf2 < input) {
firstPowerOf2 = nextPowerOf2;
nextPowerOf2 = nextPowerOf2 * 2;
}
return firstPowerOf2;
}
public long findLargestPowerOf2LessThanTheGivenNumberUsingLogBase2(long input) {
Assert.isTrue(input > 1, "Invalid input");
long temp = input;
if (input % 2 == 0) {
temp = input - 1;
}
// Find log base 2 of a given number
long power = (long) (Math.log(temp) / Math.log(2));
long result = (long) Math.pow(2, power);
return result;
}
public long findLargestPowerOf2LessThanTheGivenNumberUsingBitwiseAnd(long input) {
Assert.isTrue(input > 1, "Invalid input");
long result = 1;
for (long i = input - 1; i > 1; i--) {
if ((i & (i - 1)) == 0) {
result = i;
break;
}
}
return result;
}
public long findLargestPowerOf2LessThanTheGivenNumberUsingBitShiftApproach(long input) {
Assert.isTrue(input > 1, "Invalid input");
long result = 1;
long powerOf2;
for (long i = 0; i < Long.BYTES * 8; i++) {
powerOf2 = 1 << i;
if (powerOf2 >= input) {
break;
}
result = powerOf2;
}
return result;
}
}