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Determine if an Integer's Square Root Is an Integer in Java Article by Abdallah Sawan

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AbdallahSawan
2020-11-22 13:22:45 +02:00
parent 25b2da278a
commit 26ba335871
2 changed files with 3 additions and 3 deletions
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2
java-numbers-4/src/main/java/com/baeldung/perfectsquare/PerfectSquareUtil.java
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@@ -35,7 +35,7 @@ public class PerfectSquareUtil {
return x1 == x2 && n % x1 == 0L;
}
public static boolean isSquareNumberWithOptimization(long n) {
public static boolean isPerfectSquareWithOptimization(long n) {
if (n < 0)
return false;
switch ((int) (n & 0xF)) {

4
java-numbers-4/src/test/java/com/baeldung/perfectsquare/PerfectSquareUnitTest.java
View File

@@ -12,7 +12,7 @@ public class PerfectSquareUnitTest {
assertEquals(expectedValue, PerfectSquareUtil.isPerfectSquareByUsingSqrt(n));
assertEquals(expectedValue, PerfectSquareUtil.isPerfectSquareByUsingBinarySearch(1, Integer.MAX_VALUE, n));
assertEquals(expectedValue, PerfectSquareUtil.isPerfectSquareByUsingNewtonMethod(n));
assertEquals(expectedValue, PerfectSquareUtil.isSquareNumberWithOptimization(n));
assertEquals(expectedValue, PerfectSquareUtil.isPerfectSquareWithOptimization(n));
}
@Test
@@ -22,6 +22,6 @@ public class PerfectSquareUnitTest {
assertEquals(expectedValue, PerfectSquareUtil.isPerfectSquareByUsingSqrt(n));
assertEquals(expectedValue, PerfectSquareUtil.isPerfectSquareByUsingBinarySearch(1, Integer.MAX_VALUE, n));
assertEquals(expectedValue, PerfectSquareUtil.isPerfectSquareByUsingNewtonMethod(n));
assertEquals(expectedValue, PerfectSquareUtil.isSquareNumberWithOptimization(n));
assertEquals(expectedValue, PerfectSquareUtil.isPerfectSquareWithOptimization(n));
}
}